In mathematics, differentiation is a fundamental concept that deals with finding the rate at which a function changes. It is a key tool in calculus and is used to determine slopes, rates of change, and concavity of functions. Differentiation allows us to analyze the behavior of functions and solve a variety of real-world problems. In this topic, we will explore the basic principles of differentiation and learn how to apply them to various functions.
Differentiation is the process of finding the derivative of a function. The derivative of a function $f(x)$, denoted by $f'(x)$ or $\frac{df}{dx}$, represents the rate of change of the function with respect to the independent variable $x$. Mathematically, the derivative of a function $f(x)$ is defined as: $$f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h}$$
To find the derivative of $f(x)$, we apply the definition of differentiation: $$f'(x) = \lim_{h \to 0} \frac{2(x+h)^2 + 3(x+h) - 4 - (2x^2 + 3x - 4)}{h}$$ Expanding and simplifying, we get: $$f'(x) = \lim_{h \to 0} \frac{4x + 2h + 3 - 4}{h}$$ $$f'(x) = \lim_{h \to 0} \frac{4x + 2h - 1}{h}$$ $$f'(x) = 4x - 1$$ Therefore, the derivative of $f(x) = 2x^2 + 3x - 4$ is $f'(x) = 4x - 1$.
There are several rules that govern the differentiation of functions. These rules enable us to find the derivatives of different types of functions efficiently. Some important rules include:
Using the power rule, we have: $$g'(x) = 3 \cdot 5x^{3-1} = 15x^2$$ Therefore, the derivative of $g(x) = 5x^3$ is $g'(x) = 15x^2$.
Using the sum rule, we have: $$h'(x) = \frac{d}{dx}(3x^2) + \frac{d}{dx}(4x) = 6x + 4$$ Therefore, the derivative of $h(x) = 3x^2 + 4x$ is $h'(x) = 6x + 4$.
Using the product rule, we have: $$k'(x) = (2)(3x - 2) + (2x + 1)(3) = 6x - 4 + 6x + 3 = 12x - 1$$ Therefore, the derivative of $k(x) = (2x + 1)(3x - 2)$ is $k'(x) = 12x - 1$.
Let $u(x) = 2x^2 + 1$. Applying the chain rule, we have: $$m'(x) = 3(2x^2 + 1)^2 \cdot \frac{d}{dx}(2x^2 + 1)$$ $$m'(x) = 3(2x^2 + 1)^2 \cdot 4x = 12x(2x^2 + 1)^2$$ Therefore, the derivative of $m(x) = (2x^2 + 1)^3$ is $m'(x) = 12x(2x^2 + 1)^2$.
Solution Given $f(x) = 4x^3 - 2x^2 + 5x - 1$, we find the derivative as follows: $$f'(x) = 3 \cdot 4x^{3-1} - 2 \cdot 2x^{2-1} + 5$$ $$f'(x) = 12x^2 - 4x + 5$$
Solution For $g(x) = \frac{2}{x}$, the derivative is calculated using the power rule: $$g'(x) = -2x^{-2} = -\frac{2}{x^2}$$
Solution To find the derivative of $h(x) = e^{3x}$, we apply the chain rule: $$h'(x) = 3e^{3x}$$
Solution Given $f(x) = \sin(2x)$, the derivative is: $$f'(x) = 2\cos(2x)$$
Solution For $g(x) = \log(x^2)$, the derivative is: $$g'(x) = \frac{2}{x}$$
Create a free account to bookmark notes, download past papers, track your revision and get AI study help - free for Kenyan students.
Already have one? Log in
Join our list and we'll send fresh study notes and past papers straight to your inbox.