Grade 12 Chemistry: Acids, Bases, and Salts Notes (Kenya) | YNetStudyHub

Acids, Bases, and Salts

Grade 12 · Chemistry 4 min read

Introduction

In chemistry, the study of acids, bases, and salts is crucial as these substances play essential roles in various chemical reactions and processes. Acids are substances that donate protons (H+) in a chemical reaction, bases are substances that accept protons, and salts are formed from the reaction between an acid and a base.

Understanding the properties, reactions, and uses of acids, bases, and salts is fundamental in chemistry. Let's delve deeper into the definitions, properties, and examples of each of these substances.

Acids

Acids are substances that release hydrogen ions (H+) when dissolved in water. They have a sour taste, turn blue litmus paper red, and have a pH less than 7. Acids can be classified as strong acids (completely dissociate in water) or weak acids (partially dissociate in water).

Key Terms:

  • Hydrogen ion (H+): A positively charged ion consisting of one proton and no electrons.
  • Acidic solution: A solution with a pH less than 7.
  • Strong acid: An acid that completely dissociates in water.

Example:

Calculate the pH of a 0.1 M hydrochloric acid (HCl) solution. Given: $[\text{HCl}] = 0.1 , \text{M}$

Solution: $[\text{H+}] = 0.1 , \text{M}$ $pH = -\log[\text{H+}] = -\log(0.1) = 1$

Bases

Bases are substances that release hydroxide ions (OH-) when dissolved in water. They have a bitter taste, feel slippery, turn red litmus paper blue, and have a pH greater than 7. Bases can also be classified as strong bases (completely dissociate in water) or weak bases (partially dissociate in water).

Key Terms:

  • Hydroxide ion (OH-): A negatively charged ion consisting of one oxygen and one hydrogen atom.
  • Basic solution: A solution with a pH greater than 7.
  • Weak base: A base that partially dissociates in water.

Example:

Calculate the pH of a 0.01 M sodium hydroxide (NaOH) solution. Given: $[\text{NaOH}] = 0.01 , \text{M}$

Solution: $[\text{OH-}] = 0.01 , \text{M}$ $pOH = -\log[\text{OH-}] = -\log(0.01) = 2$ $pH = 14 - pOH = 14 - 2 = 12$

Salts

Salts are compounds formed from the neutralization reaction between an acid and a base. They are made up of a cation (positive ion) from the base and an anion (negative ion) from the acid. Salts can be acidic, basic, or neutral depending on the nature of the ions they are composed of.

Key Terms:

  • Neutralization reaction: A chemical reaction between an acid and a base to form water and a salt.
  • Cation: A positively charged ion.
  • Anion: A negatively charged ion.

Example:

Write the chemical equation for the formation of sodium chloride (NaCl) from hydrochloric acid (HCl) and sodium hydroxide (NaOH).

Solution: $HCl + NaOH \rightarrow NaCl + H_2O$

Common Mistakes

  • Confusing pH and pOH values: Remember, pH and pOH values are inversely related. Always calculate one from the other using the formula $pH = 14 - pOH$.
  • Forgetting the definitions of cations and anions: Cations are positively charged ions, while anions are negatively charged ions. Make sure to differentiate between the two in salt formations.

Key Points

  • Acids release hydrogen ions (H+) in water, have a pH less than 7, and turn blue litmus paper red.
  • Bases release hydroxide ions (OH-) in water, have a pH greater than 7, and turn red litmus paper blue.
  • Salts are formed from the neutralization of an acid and a base, composed of a cation and an anion.

Practice Questions

  1. Calculate the pH of a 0.05 M sulfuric acid (H2SO4) solution.

    Answer: $H2SO4 \rightarrow 2H^+ + SO4^{2-}$ $[\text{H+}] = 2 \times 0.05 = 0.1 , \text{M}$ $pH = -\log(0.1) = 1$

  2. Identify the cation and anion in the salt formed from the reaction between nitric acid (HNO3) and potassium hydroxide (KOH).

    Answer: $HNO3 + KOH \rightarrow KNO3 + H2O$ Cation: K+ (from KOH) Anion: NO3- (from HNO3)

  3. Determine the pH of a 0.02 M ammonia (NH3) solution.

    Answer: $NH3 + H2O \rightleftharpoons NH4^+ + OH^-$ $[\text{OH-}] = 0.02 , \text{M}$ $pOH = -\log(0.02) = 1.7$ $pH = 14 - pOH = 14 - 1.7 = 12.3$

  4. Explain why a solution of sodium chloride (NaCl) is neutral.

    Answer: NaCl dissociates into Na+ and Cl- ions in water, which do not affect the pH of the solution. Therefore, a solution of NaCl is neutral.

  5. Differentiate between a strong acid and a weak acid, giving an example of each.

    Answer: Strong acid: Completely dissociates in water (e.g., HCl) Weak acid: Partially dissociates in water (e.g., CH3COOH)

  6. Describe the properties of a basic solution and give an example of a common base.

    Answer: A basic solution has a pH greater than 7, turns red litmus paper blue, and feels slippery. An example of a common base is sodium hydroxide (NaOH).

  7. Write the chemical equation for the reaction between sulfuric acid (H2SO4) and calcium hydroxide (Ca(OH)2).

    Answer: $H2SO4 + Ca(OH)2 \rightarrow CaSO4 + 2H2O$

  8. Calculate the pOH of a 0.03 M potassium hydroxide (KOH) solution.

    Answer: $[\text{OH-}] = 0.03 , \text{M}$ $pOH = -\log(0.03) = 1.52$

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