In mathematics, a function is a relationship between a set of inputs (called the domain) and a set of possible outputs (called the range), where each input is related to exactly one output. Functions are widely used in various mathematical and real-world applications to model relationships between variables.
A function $f: A \rightarrow B$ is a rule or correspondence that assigns to each element $x$ in the set $A$ exactly one element, called $f(x)$, in the set $B$. Here, $A$ is the domain of the function and $B$ is the codomain.
Define a function $f: \mathbb{R} \rightarrow \mathbb{R}$ by $f(x) = 2x + 3$.
For $x = 4$, we have:
$$f(4) = 2(4) + 3 = 11$$
Therefore, $f(4) = 11$.
A function of the form $f(x) = mx + c$, where $m$ and $c$ are constants, is called a linear function.
Define a linear function $g(x) = 3x - 2$.
For $x = 5$, we have:
$$g(5) = 3(5) - 2 = 13$$
Therefore, $g(5) = 13$.
A function of the form $f(x) = ax^2 + bx + c$, where $a$, $b$, and $c$ are constants and $a \neq 0$, is called a quadratic function.
Define a quadratic function $h(x) = 2x^2 + 5x - 3$.
For $x = -2$, we have:
$$h(-2) = 2(-2)^2 + 5(-2) - 3 = 1$$
Therefore, $h(-2) = 1$.
A function of the form $f(x) = a \cdot b^x$, where $a$ and $b$ are constants and $b > 0$, $b \neq 1$, is called an exponential function.
Define an exponential function $f(x) = 2 \cdot 3^x$.
For $x = 0$, we have:
$$f(0) = 2 \cdot 3^0 = 2$$
Therefore, $f(0) = 2$.
Confusing Functions with Relations: Remember that a function is a special type of relation where each input has exactly one output. Not all relations are functions.
Misinterpreting Domain and Range: Be careful to correctly identify the domain and range of a function. The domain is the set of all possible inputs, while the range is the set of all possible outputs.
Answer: For $x = 3$, $$f(3) = 4(3) - 7 = 5$$ Therefore, $f(3) = 5$.
Answer: For $x = 3$, $$g(3) = (3)^2 - 6(3) + 9 = 0$$ Therefore, $g(3) = 0$.
Answer: This relation is not a function because the input $1$ is associated with two different outputs, $2$ and $5.
Answer: For $x = -1$, $$h(-1) = 3 \cdot 2^{-1} = \frac{3}{2}$$ Therefore, $h(-1) = \frac{3}{2}$.
Answer: No, the function $f(x) = x^2 + 1$ is not linear because it contains a squared term, making it a quadratic function.
In mathematics, functions are a fundamental concept that describes the relationship between two sets of numbers, the input set (domain) and the output set (range). Functions are used to represent how one quantity depends on another. A function assigns each element from the domain to exactly one element in the range. In this topic, we will explore the different types of functions, their properties, and how to work with them.
Given the linear function $f(x) = 3x - 2$, find $f(-1)$.
Answer: [ f(-1) = 3(-1) - 2 = -3 - 2 = -5 ]
Determine the vertex of the quadratic function $g(x) = x^2 + 4x - 2$.
Answer: [ \text{Vertex: } x = \frac{-4}{2 \cdot 1} = -2 \quad \text{and} \quad g(-2) = (-2)^2 + 4(-2) - 2 = 4 - 8 - 2 = -6 ]
Evaluate $h(4)$ for the exponential function $h(x) = 5^x$.
Answer: [ h(4) = 5^4 = 625 ]
Solve for $x$ in the logarithmic equation $\log_{3}(x) = 2$.
Answer: [ x = 3^2 = 9 ]
Consider the function $f(x) = \frac{1}{x}$. Find the domain of $f(x)$.
Answer: The domain of $f(x)$ is all real numbers except $x = 0$, so the domain is $x \neq 0$.
Given $g(x) = \sqrt{4x - 1}$, determine the range of $g(x)$.
Answer: The expression under the square root must be greater than or equal to zero. So, $4x - 1 \geq 0 \implies x \geq \frac{1}{4}$. Therefore, the range of $g(x)$ is $[0, ∞)$.
For the function $h(x) = e^x$, what is the inverse function of $h(x)$?
Answer: The inverse of $h(x)$ is $h^{-1}(x) = \ln(x)$.
If $f(x) = 3x^2 - 2x + 1$, determine the average rate of change over the interval $[1, 2]$.
Answer: The average rate of change is given by $\frac{f(2) - f(1)}{2 - 1}$. Calculating, [ \frac{f(2) - f(1)}{2 - 1} = \frac{7 - 2}{1} = 5 ]
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