Refraction of light is the bending of light rays as they pass from one medium to another, due to a change in the speed of light. This phenomenon occurs because light waves change speed when they move from one medium to another, causing them to change direction. The amount of bending depends on the speed of light in the two media and the angle at which the light enters the new medium.
When light travels from one medium to another, it changes speed and bends. The bending of light is governed by Snell's Law, which states:
$$n_1 \times \sin(\theta_1) = n_2 \times \sin(\theta_2)$$
Where:
Given that the refractive index of medium A is 1.5 and medium B is 1.2, calculate the angle of refraction if the angle of incidence is 30 degrees.
$$1.5 \times \sin(30^\circ) = 1.2 \times \sin(\theta_2)$$ $$\sin(\theta_2) = \frac{1.5}{1.2} \times \sin(30^\circ)$$ $$\theta_2 = \sin^{-1} \left( \frac{1.5}{1.2} \times \sin(30^\circ) \right)$$
The refractive index of a medium is a measure of how much the speed of light is reduced in that medium compared to a vacuum. It is defined as the ratio of the speed of light in a vacuum to the speed of light in the medium.
$$\text{Refractive index (}n\text{)} = \frac{\text{Speed of light in vacuum}}{\text{Speed of light in medium}}$$
If the speed of light in a medium is $2 \times 10^8 , \text{m/s}$ and the speed of light in vacuum is $3 \times 10^8 , \text{m/s}$, what is the refractive index of the medium?
$$n = \frac{3 \times 10^8}{2 \times 10^8} = 1.5$$
Total internal reflection occurs when light is fully reflected back into the same medium due to the angle of incidence being greater than the critical angle. The critical angle is the angle of incidence that produces an angle of refraction of 90 degrees.
$$\text{Critical angle} = \sin^{-1} \left( \frac{n_2}{n_1} \right)$$
If the refractive index of medium A is 1.5 and medium B is 1.2, calculate the critical angle for total internal reflection.
$$\text{Critical angle} = \sin^{-1} \left( \frac{1.2}{1.5} \right)$$
Lenses are transparent objects that refract light to converge or diverge the light rays. There are two main types of lenses: convex lenses (thicker in the middle, converge light rays) and concave lenses (thinner in the middle, diverge light rays).
If a convex lens has a focal length of 10 cm and an object is placed 20 cm away from the lens, calculate the image distance using the lens formula:
$$\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$$
Given $f = 10 , \text{cm}$, $u = -20 , \text{cm}$:
$$\frac{1}{10} = \frac{1}{v} + \frac{1}{20}$$ $$\frac{1}{v} = \frac{1}{10} - \frac{1}{20}$$ $$\frac{1}{v} = \frac{2 - 1}{20}$$ $$\frac{1}{v} = \frac{1}{20}$$ $$v = 20 , \text{cm}$$
Dispersion is the separation of light into its different colors (wavelengths) when it passes through a prism. Different colors of light have different refractive indices, causing them to bend by different amounts.
If white light is passed through a prism, which color will bend the most and which will bend the least?
The color that bends the most is violet, as it has the shortest wavelength and highest refractive index. The color that bends the least is red, with the longest wavelength and lowest refractive index.
Answer: $$1 \times \sin(45^\circ) = 1.33 \times \sin(\theta_2)$$ $$\theta_2 = \sin^{-1} \left( \frac{1}{1.33} \times \sin(45^\circ) \right)$$
Answer: $$\text{Critical angle} = \sin^{-1} \left( \frac{1.0}{1.5} \right)$$
Answer: Use the lens formula: $\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$
Answer: Raindrops act as prisms, dispersing sunlight into its different colors due to their different refractive indices.
Answer: Total internal reflection occurs within a medium, with the light fully reflected back. Regular reflection occurs at the boundary between two media.
Answer: Given the speed of light in vacuum is $3 \times 10^8 , \text{m/s}$, use $n = \frac{3 \times 10^8}{2.5 \times 10^8}$.
Answer: A convex lens converges light rays, bringing them to a focus point.
Answer: Due to refraction, light rays from the pencil bend at the water-air boundary, causing the pencil to appear bent.
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